Selecting the Correct Solution

Oct 13, 2025 by pynkocean.com 144 views

Introduction

In this article, we will be solving a given equation and examining a table to select the accurate number of each type of solution. The equation to be solved is $\frac{3}{x} - \frac{x}{x+6} = \frac{18}{x^2+6x}$ . We will break down the solution step by step and then examine the table to select the correct solution.

Step 1: Simplify the Equation

The first step in solving the equation is to simplify it by combining the fractions on the left-hand side. To do this, we need to find a common denominator for the two fractions.

$\frac{3}{x} - \frac{x}{x+6} = \frac{18}{x^2+6x}$

The common denominator for the two fractions is $x(x+6)$ .

$\frac{3(x+6)}{x(x+6)} - \frac{x(x)}{x(x+6)} = \frac{18}{x^2+6x}$

Simplifying the fractions, we get:

$\frac{3x+18}{x(x+6)} - \frac{x^2}{x(x+6)} = \frac{18}{x^2+6x}$

Step 2: Combine the Fractions

Now that we have a common denominator, we can combine the fractions on the left-hand side.

$\frac{3x+18-x^2}{x(x+6)} = \frac{18}{x^2+6x}$

Simplifying the numerator, we get:

$\frac{-x^2+3x+18}{x(x+6)} = \frac{18}{x^2+6x}$

Step 3: Cross-Multiply

To get rid of the fractions, we can cross-multiply the two sides of the equation.

$(-x^2+3x+18)(x^2+6x) = 18x(x+6)$

Expanding the left-hand side, we get:

$-x^4-6x^3+3x^3+18x^2+18x^2+108x = 18x^2+108x$

Simplifying the equation, we get:

$-x^4-3x^3+36x^2+108x = 18x^2+108x$

Step 4: Move All Terms to One Side

To solve for $x$ , we need to move all the terms to one side of the equation.

$-x^4-3x^3+36x^2+108x-18x^2-108x = 0$

Simplifying the equation, we get:

$-x^4-3x^3+18x^2 = 0$

Step 5: Factor the Equation

The equation can be factored as follows:

$-x^4-3x^3+18x^2 = -x^2(x^2+3x-18) = 0$

Step 6: Solve for $x$

To solve for $x$ , we need to set each factor equal to zero and solve for $x$ .

$-x^2 = 0 \Rightarrow x = 0$

$x^2+3x-18 = 0 \Rightarrow x = -6, 3$

Conclusion

The solutions to the equation are $x = 0, -6, 3$ . Now, let's examine the table to select the accurate number of each type of solution.

Table

Solution Type	Number of Solutions
Real Solutions	3
Complex Solutions	0
Rational Solutions	2
Irrational Solutions	1

Selecting the Correct Solution

Based on the table, we can select the accurate number of each type of solution.

Real Solutions: 3
Complex Solutions: 0
Rational Solutions: 2
Irrational Solutions: 1

Therefore, the correct solution is:

Real Solutions: 3
Complex Solutions: 0
Rational Solutions: 2
Irrational Solutions: 1

Discussion

The equation $\frac{3}{x} - \frac{x}{x+6} = \frac{18}{x^2+6x}$ has three real solutions: $x = 0, -6, 3$ . The solutions can be classified into different types: real, complex, rational, and irrational. The table provides the accurate number of each type of solution. By examining the table, we can select the correct solution.

Conclusion

In conclusion, the equation $\frac{3}{x} - \frac{x}{x+6} = \frac{18}{x^2+6x}$ has three real solutions: $x = 0, -6, 3$ . The solutions can be classified into different types: real, complex, rational, and irrational. The table provides the accurate number of each type of solution. By examining the table, we can select the correct solution.

References

[1] "Algebra" by Michael Artin
[2] "Calculus" by Michael Spivak
[3] "Linear Algebra" by Jim Hefferon

Keywords

Equation
Solution
Real Solutions
Complex Solutions
Rational Solutions
Irrational Solutions
Table
Classification
Algebra
Calculus
Linear Algebra
Frequently Asked Questions (FAQs) =====================================

Q: What is the equation $\frac{3}{x} - \frac{x}{x+6} = \frac{18}{x^2+6x}$ ?

A: The equation is a rational equation that involves fractions with variables in the numerator and denominator.

Q: How do I simplify the equation?

A: To simplify the equation, you need to find a common denominator for the two fractions on the left-hand side and then combine them.

Q: What is the common denominator for the two fractions?

A: The common denominator for the two fractions is $x(x+6)$ .

Q: How do I cross-multiply the two sides of the equation?

A: To cross-multiply the two sides of the equation, you need to multiply both sides by the denominators of the fractions.

Q: What is the result of cross-multiplying the two sides of the equation?

A: The result of cross-multiplying the two sides of the equation is $(-x^2+3x+18)(x^2+6x) = 18x(x+6)$ .

Q: How do I solve for $x$ ?

A: To solve for $x$ , you need to set each factor equal to zero and solve for $x$ .

Q: What are the solutions to the equation?

A: The solutions to the equation are $x = 0, -6, 3$ .

Q: How do I classify the solutions?

A: To classify the solutions, you need to determine whether they are real, complex, rational, or irrational.

Q: What is the table that provides the accurate number of each type of solution?

A: The table is:

Solution Type	Number of Solutions
Real Solutions	3
Complex Solutions	0
Rational Solutions	2
Irrational Solutions	1

Q: How do I select the correct solution?

A: To select the correct solution, you need to examine the table and choose the correct number of each type of solution.

Q: What are the correct solutions?

A: The correct solutions are:

Real Solutions: 3
Complex Solutions: 0
Rational Solutions: 2
Irrational Solutions: 1

Q: Why is it important to classify the solutions?

A: It is important to classify the solutions because it helps to understand the nature of the solutions and how they relate to the original equation.

Q: What are some common mistakes to avoid when solving equations?

A: Some common mistakes to avoid when solving equations include:

Not simplifying the equation enough
Not cross-multiplying the two sides of the equation
Not setting each factor equal to zero and solving for $x$
Not classifying the solutions correctly

Q: How can I practice solving equations?

A: You can practice solving equations by working through example problems and exercises. You can also try solving equations on your own and then checking your work with a calculator or by asking a teacher or tutor for help.

Q: What are some resources for learning more about solving equations?

A: Some resources for learning more about solving equations include:

Textbooks on algebra and calculus
Online tutorials and videos
Practice problems and exercises
Teachers and tutors who can provide one-on-one instruction and feedback.