Substituting the Known Solution

Oct 13, 2025 by pynkocean.com 22 views

Introduction

In mathematics, solving quadratic equations is a fundamental concept that involves finding the values of variables that satisfy a given equation. Quadratic equations are of the form $ax^2 + bx + c = 0$ , where $a$ , $b$ , and $c$ are constants. In this article, we will explore how to find the second solution of a quadratic equation when one solution is already known.

The Given Equation

The given equation is $(6x + 4)^2 = \square$ . We are told that $x = -\frac{4}{3}$ is one solution of this equation. Our goal is to find the other solution.

Expanding the Equation

To find the other solution, we need to expand the given equation. We can do this by using the formula $(a + b)^2 = a^2 + 2ab + b^2$ . In this case, $a = 6x$ and $b = 4$ . Therefore, we have:

$(6x + 4)^2 = (6x)^2 + 2(6x)(4) + 4^2$

Simplifying the Equation

Now, we can simplify the equation by evaluating the expressions:

$(6x)^2 = 36x^2$

$2(6x)(4) = 48x$

$4^2 = 16$

Therefore, the equation becomes:

$36x^2 + 48x + 16 = \square$

Substituting the Known Solution

We are given that $x = -\frac{4}{3}$ is one solution of the equation. We can substitute this value into the equation to get:

$36(-\frac{4}{3})^2 + 48(-\frac{4}{3}) + 16 = \square$

Evaluating the Expression

Now, we can evaluate the expression:

$36(-\frac{4}{3})^2 = 36(\frac{16}{9}) = \frac{576}{9} = 64$

$48(-\frac{4}{3}) = -64$

Therefore, the equation becomes:

$64 - 64 + 16 = \square$

Simplifying the Equation

Now, we can simplify the equation by combining like terms:

$16 = \square$

Finding the Second Solution

Since the equation is an identity, we know that it is true for all values of $x$ . Therefore, we can set the equation equal to zero and solve for $x$ :

$36x^2 + 48x + 16 = 0$

Factoring the Quadratic

We can factor the quadratic equation as follows:

$(6x + 4)^2 = 0$

Solving for x

Now, we can solve for $x$ :

$6x + 4 = 0$

$6x = -4$

$x = -\frac{4}{6}$

$x = -\frac{2}{3}$

Conclusion

In this article, we have shown how to find the second solution of a quadratic equation when one solution is already known. We started with the given equation $(6x + 4)^2 = \square$ and expanded it to get $36x^2 + 48x + 16 = \square$ . We then substituted the known solution $x = -\frac{4}{3}$ into the equation and evaluated the expression. Finally, we simplified the equation and factored it to get $(6x + 4)^2 = 0$ . Solving for $x$ , we found that the second solution is $x = -\frac{2}{3}$ .

Final Answer

Introduction

In our previous article, we explored how to find the second solution of a quadratic equation when one solution is already known. In this article, we will provide a Q&A guide to help you better understand the concept of solving quadratic equations.

Q: What is a quadratic equation?

A: A quadratic equation is a polynomial equation of degree two, which means the highest power of the variable is two. It is of the form $ax^2 + bx + c = 0$ , where $a$ , $b$ , and $c$ are constants.

Q: How do I solve a quadratic equation?

A: To solve a quadratic equation, you can use various methods such as factoring, quadratic formula, or graphing. The method you choose depends on the complexity of the equation and your personal preference.

Q: What is the quadratic formula?

A: The quadratic formula is a mathematical formula that gives the solutions to a quadratic equation. It is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Q: How do I use the quadratic formula?

A: To use the quadratic formula, you need to identify the values of $a$ , $b$ , and $c$ in the quadratic equation. Then, you can plug these values into the formula and simplify to get the solutions.

Q: What is the difference between the quadratic formula and factoring?

A: The quadratic formula and factoring are two different methods of solving quadratic equations. Factoring involves expressing the quadratic equation as a product of two binomials, while the quadratic formula involves using a formula to find the solutions.

Q: Can I use the quadratic formula to solve all quadratic equations?

A: Yes, the quadratic formula can be used to solve all quadratic equations. However, it may not always be the most efficient method, especially for simple equations that can be factored easily.

Q: How do I choose between the quadratic formula and factoring?

A: To choose between the quadratic formula and factoring, you need to consider the complexity of the equation and your personal preference. If the equation is simple and can be factored easily, factoring may be the better choice. However, if the equation is complex or cannot be factored easily, the quadratic formula may be a better option.

Q: What are some common mistakes to avoid when solving quadratic equations?

A: Some common mistakes to avoid when solving quadratic equations include:

Not identifying the values of $a$ , $b$ , and $c$ correctly
Not simplifying the equation correctly
Not using the correct method for the equation (e.g. using the quadratic formula when factoring is possible)
Not checking the solutions for extraneous solutions

Q: How do I check my solutions for extraneous solutions?

A: To check your solutions for extraneous solutions, you need to plug the solutions back into the original equation and check if they satisfy the equation. If they do not satisfy the equation, they are extraneous solutions and should be discarded.

Conclusion

In this article, we have provided a Q&A guide to help you better understand the concept of solving quadratic equations. We have covered topics such as the quadratic formula, factoring, and common mistakes to avoid. By following these tips and practicing regularly, you can become proficient in solving quadratic equations and tackle more complex math problems with confidence.

Final Answer

The final answer is $\boxed{0}$ , but the real answer is that solving quadratic equations is a skill that takes practice and patience to develop.